1x(10x+8)=-3(x+1)

Solution for 1x(10x+8)=-3(x+1) equation:

1x(10x+8)=-3(x+1)

We move all terms to the left:

1x(10x+8)-(-3(x+1))=0

We multiply parentheses

10x^2+8x-(-3(x+1))=0


We calculate terms in parentheses: -(-3(x+1)), so:

-3(x+1)

We multiply parentheses

-3x-3

Back to the equation:

-(-3x-3)


We get rid of parentheses

10x^2+8x+3x+3=0

We add all the numbers together, and all the variables

10x^2+11x+3=0

a = 10; b = 11; c = +3;
Δ = b2-4ac
Δ = 112-4·10·3
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-1}{2*10}=\frac{-12}{20}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+1}{2*10}=\frac{-10}{20}
=-1/2
$