1x(2x+9)=180

Solution for 1x(2x+9)=180 equation:

1x(2x+9)=180

We move all terms to the left:

1x(2x+9)-(180)=0

We multiply parentheses

2x^2+9x-180=0

a = 2; b = 9; c = -180;
Δ = b2-4ac
Δ = 92-4·2·(-180)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-39}{2*2}=\frac{-48}{4}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+39}{2*2}=\frac{30}{4}
=7+1/2
$