1x(3x+5)=-9+13

Solution for 1x(3x+5)=-9+13 equation:

1x(3x+5)=-9+13

We move all terms to the left:

1x(3x+5)-(-9+13)=0

We add all the numbers together, and all the variables

1x(3x+5)-4=0

We multiply parentheses

3x^2+5x-4=0

a = 3; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·3·(-4)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{73}}{2*3}=\frac{-5-\sqrt{73}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{73}}{2*3}=\frac{-5+\sqrt{73}}{6}
$