1x(6x-9)=6x+5

Solution for 1x(6x-9)=6x+5 equation:

1x(6x-9)=6x+5

We move all terms to the left:

1x(6x-9)-(6x+5)=0

We multiply parentheses

6x^2-9x-(6x+5)=0

We get rid of parentheses

6x^2-9x-6x-5=0

We add all the numbers together, and all the variables

6x^2-15x-5=0

a = 6; b = -15; c = -5;
Δ = b2-4ac
Δ = -152-4·6·(-5)
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{345}}{2*6}=\frac{15-\sqrt{345}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{345}}{2*6}=\frac{15+\sqrt{345}}{12}
$