1x(8x+5)=12x(6x+1)

Solution for 1x(8x+5)=12x(6x+1) equation:

1x(8x+5)=12x(6x+1)

We move all terms to the left:

1x(8x+5)-(12x(6x+1))=0

We multiply parentheses

8x^2+5x-(12x(6x+1))=0


We calculate terms in parentheses: -(12x(6x+1)), so:

12x(6x+1)

We multiply parentheses

72x^2+12x

Back to the equation:

-(72x^2+12x)


We get rid of parentheses

8x^2-72x^2+5x-12x=0

We add all the numbers together, and all the variables

-64x^2-7x=0

a = -64; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-64)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-64}=\frac{0}{-128}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-64}=\frac{14}{-128}
=-7/64
$