1x(x-38)=180

Solution for 1x(x-38)=180 equation:

1x(x-38)=180

We move all terms to the left:

1x(x-38)-(180)=0

We multiply parentheses

x^2-38x-180=0

a = 1; b = -38; c = -180;
Δ = b2-4ac
Δ = -382-4·1·(-180)
Δ = 2164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2164}=\sqrt{4*541}=\sqrt{4}*\sqrt{541}=2\sqrt{541}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-2\sqrt{541}}{2*1}=\frac{38-2\sqrt{541}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+2\sqrt{541}}{2*1}=\frac{38+2\sqrt{541}}{2}
$