1x+(-20)=3x+12

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Solution for 1x+(-20)=3x+12 equation: 



1x+(-20)=3x+12

We move all terms to the left:

1x+(-20)-(3x+12)=0

We add all the numbers together, and all the variables

x-(3x+12)-20=0

We get rid of parentheses

x-3x-12-20=0

We add all the numbers together, and all the variables

-2x-32=0

We move all terms containing x to the left, all other terms to the right

-2x=32

x=32/-2

x=-16

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