1x+(0.23/x)=1

Solution for 1x+(0.23/x)=1 equation:

1x+(0.23/x)=1

We move all terms to the left:

1x+(0.23/x)-(1)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1x+(+0.23/x)-1=0

We add all the numbers together, and all the variables

x+(+0.23/x)-1=0

We get rid of parentheses

x+0.23/x-1=0

We multiply all the terms by the denominator


x*x-1*x+0.23=0

We add all the numbers together, and all the variables

-1x+x*x+0.23=0

Wy multiply elements

x^2-1x+0.23=0

a = 1; b = -1; c = +0.23;
Δ = b2-4ac
Δ = -12-4·1·0.23
Δ = 0.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.08}}{2*1}=\frac{1-\sqrt{0.08}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.08}}{2*1}=\frac{1+\sqrt{0.08}}{2}
$