1x+(2+x)+3(6+x)=80

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Solution for 1x+(2+x)+3(6+x)=80 equation: 



1x+(2+x)+3(6+x)=80

We move all terms to the left:

1x+(2+x)+3(6+x)-(80)=0

We add all the numbers together, and all the variables

1x+(x+2)+3(x+6)-80=0

We add all the numbers together, and all the variables

x+(x+2)+3(x+6)-80=0

We multiply parentheses

x+(x+2)+3x+18-80=0

We get rid of parentheses

x+x+3x+2+18-80=0

We add all the numbers together, and all the variables

5x-60=0

We move all terms containing x to the left, all other terms to the right

5x=60

x=60/5

x=12

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