1x+(25-x)x2=38

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Solution for 1x+(25-x)x2=38 equation: 



1x+(25-x)x2=38

We move all terms to the left:

1x+(25-x)x2-(38)=0

We add all the numbers together, and all the variables

1x+(-1x+25)x2-38=0

We add all the numbers together, and all the variables

x+(-1x+25)x2-38=0

We multiply parentheses

-1x^3+25x^2+x-38=0

We do not support expression: x^3

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