1x+(x+3)+1x+(x+3)=34

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Solution for 1x+(x+3)+1x+(x+3)=34 equation: 



1x+(x+3)+1x+(x+3)=34

We move all terms to the left:

1x+(x+3)+1x+(x+3)-(34)=0

We add all the numbers together, and all the variables

2x+(x+3)+(x+3)-34=0

We get rid of parentheses

2x+x+x+3+3-34=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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