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1x+(x+3)+1x+(x+3)=34
We move all terms to the left:
1x+(x+3)+1x+(x+3)-(34)=0
We add all the numbers together, and all the variables
2x+(x+3)+(x+3)-34=0
We get rid of parentheses
2x+x+x+3+3-34=0
We add all the numbers together, and all the variables
4x-28=0
We move all terms containing x to the left, all other terms to the right
4x=28
x=28/4
x=7
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