1x+1(.25x)=4000

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Solution for 1x+1(.25x)=4000 equation: 



1x+1(.25x)=4000

We move all terms to the left:

1x+1(.25x)-(4000)=0

We add all the numbers together, and all the variables

1x+1(+.25x)-4000=0

We add all the numbers together, and all the variables

x+1(+.25x)-4000=0

We move all terms containing x to the left, all other terms to the right

x+1(+.25x)=4000

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