1x+1/4x=210

Solution for 1x+1/4x=210 equation:

1x+1/4x=210

We move all terms to the left:

1x+1/4x-(210)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

x+1/4x-210=0

We multiply all the terms by the denominator


x*4x-210*4x+1=0

Wy multiply elements

4x^2-840x+1=0

a = 4; b = -840; c = +1;
Δ = b2-4ac
Δ = -8402-4·4·1
Δ = 705584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{705584}=\sqrt{16*44099}=\sqrt{16}*\sqrt{44099}=4\sqrt{44099}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-840)-4\sqrt{44099}}{2*4}=\frac{840-4\sqrt{44099}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-840)+4\sqrt{44099}}{2*4}=\frac{840+4\sqrt{44099}}{8}
$