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1x+1/5x=24
We move all terms to the left:
1x+1/5x-(24)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
x+1/5x-24=0
We multiply all the terms by the denominator
x*5x-24*5x+1=0
Wy multiply elements
5x^2-120x+1=0
a = 5; b = -120; c = +1;
Δ = b2-4ac
Δ = -1202-4·5·1
Δ = 14380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14380}=\sqrt{4*3595}=\sqrt{4}*\sqrt{3595}=2\sqrt{3595}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-2\sqrt{3595}}{2*5}=\frac{120-2\sqrt{3595}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+2\sqrt{3595}}{2*5}=\frac{120+2\sqrt{3595}}{10} $
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