1x+10(9-x)-27=10x+(9-x)

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Solution for 1x+10(9-x)-27=10x+(9-x) equation: 



1x+10(9-x)-27=10x+(9-x)

We move all terms to the left:

1x+10(9-x)-27-(10x+(9-x))=0

We add all the numbers together, and all the variables

1x+10(-1x+9)-(10x+(-1x+9))-27=0

We add all the numbers together, and all the variables

x+10(-1x+9)-(10x+(-1x+9))-27=0

We multiply parentheses

x-10x-(10x+(-1x+9))+90-27=0



We calculate terms in parentheses: -(10x+(-1x+9)), so:

10x+(-1x+9)

We get rid of parentheses

10x-1x+9

We add all the numbers together, and all the variables

9x+9

Back to the equation:

-(9x+9)



We add all the numbers together, and all the variables

-9x-(9x+9)+63=0

We get rid of parentheses

-9x-9x-9+63=0

We add all the numbers together, and all the variables

-18x+54=0

We move all terms containing x to the left, all other terms to the right

-18x=-54

x=-54/-18

x=+3

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