1x+1=8(2x+5)

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Solution for 1x+1=8(2x+5) equation: 



1x+1=8(2x+5)

We move all terms to the left:

1x+1-(8(2x+5))=0

We add all the numbers together, and all the variables

x-(8(2x+5))+1=0



We calculate terms in parentheses: -(8(2x+5)), so:

8(2x+5)

We multiply parentheses

16x+40

Back to the equation:

-(16x+40)



We get rid of parentheses

x-16x-40+1=0

We add all the numbers together, and all the variables

-15x-39=0

We move all terms containing x to the left, all other terms to the right

-15x=39

x=39/-15

x=-2+3/5

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