1x+2(x+10)=9(x+3)+5

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Solution for 1x+2(x+10)=9(x+3)+5 equation: 



1x+2(x+10)=9(x+3)+5

We move all terms to the left:

1x+2(x+10)-(9(x+3)+5)=0

We add all the numbers together, and all the variables

x+2(x+10)-(9(x+3)+5)=0

We multiply parentheses

x+2x-(9(x+3)+5)+20=0



We calculate terms in parentheses: -(9(x+3)+5), so:

9(x+3)+5

We multiply parentheses

9x+27+5

We add all the numbers together, and all the variables

9x+32

Back to the equation:

-(9x+32)



We add all the numbers together, and all the variables

3x-(9x+32)+20=0

We get rid of parentheses

3x-9x-32+20=0

We add all the numbers together, and all the variables

-6x-12=0

We move all terms containing x to the left, all other terms to the right

-6x=12

x=12/-6

x=-2

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