1x+2/3x+2/5=4/5x

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Solution for 1x+2/3x+2/5=4/5x equation:



1x+2/3x+2/5=4/5x
We move all terms to the left:
1x+2/3x+2/5-(4/5x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
1x+2/3x-(+4/5x)+2/5=0
We add all the numbers together, and all the variables
x+2/3x-(+4/5x)+2/5=0
We get rid of parentheses
x+2/3x-4/5x+2/5=0
We calculate fractions
x+250x/375x^2+(-12x)/375x^2+6x/375x^2=0
We multiply all the terms by the denominator
x*375x^2+250x+(-12x)+6x=0
We add all the numbers together, and all the variables
256x+x*375x^2+(-12x)=0
Wy multiply elements
375x^3+256x+(-12x)=0
We get rid of parentheses
375x^3+256x-12x=0
We do not support expression: x^3

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