1x+2=3(x+2)

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Solution for 1x+2=3(x+2) equation: 



1x+2=3(x+2)

We move all terms to the left:

1x+2-(3(x+2))=0

We add all the numbers together, and all the variables

x-(3(x+2))+2=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

x-3x-6+2=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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