1x+2=3(x-4)

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Solution for 1x+2=3(x-4) equation: 



1x+2=3(x-4)

We move all terms to the left:

1x+2-(3(x-4))=0

We add all the numbers together, and all the variables

x-(3(x-4))+2=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

x-3x+12+2=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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