1x+3(6-x)=20

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Solution for 1x+3(6-x)=20 equation: 



1x+3(6-x)=20

We move all terms to the left:

1x+3(6-x)-(20)=0

We add all the numbers together, and all the variables

1x+3(-1x+6)-20=0

We add all the numbers together, and all the variables

x+3(-1x+6)-20=0

We multiply parentheses

x-3x+18-20=0

We add all the numbers together, and all the variables

-2x-2=0

We move all terms containing x to the left, all other terms to the right

-2x=2

x=2/-2

x=-1

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