1x+3(x/2)+4(3x/4)=624

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Solution for 1x+3(x/2)+4(3x/4)=624 equation: 



1x+3(x/2)+4(3x/4)=624

We move all terms to the left:

1x+3(x/2)+4(3x/4)-(624)=0

We add all the numbers together, and all the variables

1x+3(+x/2)+4(+3x/4)-624=0

We add all the numbers together, and all the variables

x+3(+x/2)+4(+3x/4)-624=0

We multiply parentheses

x+3x+12x-624=0

We add all the numbers together, and all the variables

16x-624=0

We move all terms containing x to the left, all other terms to the right

16x=624

x=624/16

x=39

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