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1x+45=4(5-x)
We move all terms to the left:
1x+45-(4(5-x))=0
We add all the numbers together, and all the variables
1x-(4(-1x+5))+45=0
We add all the numbers together, and all the variables
x-(4(-1x+5))+45=0
We calculate terms in parentheses: -(4(-1x+5)), so:We get rid of parentheses
4(-1x+5)
We multiply parentheses
-4x+20
Back to the equation:
-(-4x+20)
x+4x-20+45=0
We add all the numbers together, and all the variables
5x+25=0
We move all terms containing x to the left, all other terms to the right
5x=-25
x=-25/5
x=-5
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