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1x+8=2(3x+4)
We move all terms to the left:
1x+8-(2(3x+4))=0
We add all the numbers together, and all the variables
x-(2(3x+4))+8=0
We calculate terms in parentheses: -(2(3x+4)), so:We get rid of parentheses
2(3x+4)
We multiply parentheses
6x+8
Back to the equation:
-(6x+8)
x-6x-8+8=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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