1x-(8/3)x=-10

Solution for 1x-(8/3)x=-10 equation:

1x-(8/3)x=-10

We move all terms to the left:

1x-(8/3)x-(-10)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1x-(+8/3)x-(-10)=0

We add all the numbers together, and all the variables

x-(+8/3)x+10=0

We multiply parentheses

-8x^2+x+10=0

a = -8; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·(-8)·10
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{321}}{2*-8}=\frac{-1-\sqrt{321}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{321}}{2*-8}=\frac{-1+\sqrt{321}}{-16}
$