1x-1/4(12-x)=x+3(4-x)-2x

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Solution for 1x-1/4(12-x)=x+3(4-x)-2x equation: 



1x-1/4(12-x)=x+3(4-x)-2x

We move all terms to the left:

1x-1/4(12-x)-(x+3(4-x)-2x)=0



Domain of the equation: 4(12-x)!=0

x∈R



We add all the numbers together, and all the variables

1x-1/4(-1x+12)-(x+3(-1x+4)-2x)=0

We add all the numbers together, and all the variables

x-1/4(-1x+12)-(x+3(-1x+4)-2x)=0

We multiply all the terms by the denominator


x*4(-1x+12)-((x+3(-1x+4)-2x))*4(-1x+12)-1=0



We calculate terms in parentheses: -((x+3(-1x+4)-2x))*4(-1x+12), so:

(x+3(-1x+4)-2x))*4(-1x+12

We add all the numbers together, and all the variables

-1x+(x+3(-1x+4)-2x))*4(+12

Back to the equation:

-(-1x+(x+3(-1x+4)-2x))*4(+12)



We add all the numbers together, and all the variables

x*4(-1x+12)-(-1x+(x+3(-1x+4)-2x))*412-1=0

Wy multiply elements

4x^2(--(-1x+(x+3(-1x+4)-2x))*412-1=0

We use the square of the difference formula

4x^2(+(-1x+(x+3(-1x+4)-2x))*412-1=0

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