1x-18=2(3x-12)+4

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Solution for 1x-18=2(3x-12)+4 equation: 



1x-18=2(3x-12)+4

We move all terms to the left:

1x-18-(2(3x-12)+4)=0

We add all the numbers together, and all the variables

x-(2(3x-12)+4)-18=0



We calculate terms in parentheses: -(2(3x-12)+4), so:

2(3x-12)+4

We multiply parentheses

6x-24+4

We add all the numbers together, and all the variables

6x-20

Back to the equation:

-(6x-20)



We get rid of parentheses

x-6x+20-18=0

We add all the numbers together, and all the variables

-5x+2=0

We move all terms containing x to the left, all other terms to the right

-5x=-2

x=-2/-5

x=2/5

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