1x-2.1(x+2)=3(x+1.5)

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Solution for 1x-2.1(x+2)=3(x+1.5) equation: 



1x-2.1(x+2)=3(x+1.5)

We move all terms to the left:

1x-2.1(x+2)-(3(x+1.5))=0

We add all the numbers together, and all the variables

x-2.1(x+2)-(3(x+1.5))=0

We multiply parentheses

x-2.1x-(3(x+1.5))-4.2=0



We calculate terms in parentheses: -(3(x+1.5)), so:

3(x+1.5)

We multiply parentheses

3x+4.5

Back to the equation:

-(3x+4.5)



We add all the numbers together, and all the variables

-1.1x-(3x+4.5)-4.2=0

We get rid of parentheses

-1.1x-3x-4.5-4.2=0

We add all the numbers together, and all the variables

-4.1x-8.7=0

We move all terms containing x to the left, all other terms to the right

-4.1x=8.7

x=8.7/-4.1

x=-2+0.5/4.1

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