1x-5(x+1)=7(6x-1)+2

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Solution for 1x-5(x+1)=7(6x-1)+2 equation:


Simplifying
1x + -5(x + 1) = 7(6x + -1) + 2

Reorder the terms:
1x + -5(1 + x) = 7(6x + -1) + 2
1x + (1 * -5 + x * -5) = 7(6x + -1) + 2
1x + (-5 + -5x) = 7(6x + -1) + 2

Reorder the terms:
-5 + 1x + -5x = 7(6x + -1) + 2

Combine like terms: 1x + -5x = -4x
-5 + -4x = 7(6x + -1) + 2

Reorder the terms:
-5 + -4x = 7(-1 + 6x) + 2
-5 + -4x = (-1 * 7 + 6x * 7) + 2
-5 + -4x = (-7 + 42x) + 2

Reorder the terms:
-5 + -4x = -7 + 2 + 42x

Combine like terms: -7 + 2 = -5
-5 + -4x = -5 + 42x

Add '5' to each side of the equation.
-5 + 5 + -4x = -5 + 5 + 42x

Combine like terms: -5 + 5 = 0
0 + -4x = -5 + 5 + 42x
-4x = -5 + 5 + 42x

Combine like terms: -5 + 5 = 0
-4x = 0 + 42x
-4x = 42x

Solving
-4x = 42x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-42x' to each side of the equation.
-4x + -42x = 42x + -42x

Combine like terms: -4x + -42x = -46x
-46x = 42x + -42x

Combine like terms: 42x + -42x = 0
-46x = 0

Divide each side by '-46'.
x = 0

Simplifying
x = 0

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