1x-8/x=7/2

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Solution for 1x-8/x=7/2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1*x-(8/x) = 7/2 // - 7/2

1*x-(8/x)-(7/2) = 0

x-8*x^-1-7/2 = 0

1*x^1-8*x^-1-7/2*x^0 = 0

(1*x^2-7/2*x^1-8*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-7/2*x^1-8*x^0) = 0

x^1

x^2+(-7/2)*x-8 = 0

x^2+(-7/2)*x-8 = 0

DELTA = (-7/2)^2-(-8*1*4)

DELTA = 177/4

DELTA > 0

x = ((177/4)^(1/2)-(-7/2))/(1*2) or x = (-(-7/2)-(177/4)^(1/2))/(1*2)

x = ((177/4)^(1/2)+7/2)/2 or x = (7/2-(177/4)^(1/2))/2

x in { (7/2-(177/4)^(1/2))/2, ((177/4)^(1/2)+7/2)/2} 

x in { (7/2-(177/4)^(1/2))/2, ((177/4)^(1/2)+7/2)/2 }

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