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1x-9=1/4x+3
We move all terms to the left:
1x-9-(1/4x+3)=0
Domain of the equation: 4x+3)!=0We add all the numbers together, and all the variables
x∈R
x-(1/4x+3)-9=0
We get rid of parentheses
x-1/4x-3-9=0
We multiply all the terms by the denominator
x*4x-3*4x-9*4x-1=0
Wy multiply elements
4x^2-12x-36x-1=0
We add all the numbers together, and all the variables
4x^2-48x-1=0
a = 4; b = -48; c = -1;
Δ = b2-4ac
Δ = -482-4·4·(-1)
Δ = 2320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2320}=\sqrt{16*145}=\sqrt{16}*\sqrt{145}=4\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-4\sqrt{145}}{2*4}=\frac{48-4\sqrt{145}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+4\sqrt{145}}{2*4}=\frac{48+4\sqrt{145}}{8} $
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