1x-9=8(2x+3)-18

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Solution for 1x-9=8(2x+3)-18 equation: 



1x-9=8(2x+3)-18

We move all terms to the left:

1x-9-(8(2x+3)-18)=0

We add all the numbers together, and all the variables

x-(8(2x+3)-18)-9=0



We calculate terms in parentheses: -(8(2x+3)-18), so:

8(2x+3)-18

We multiply parentheses

16x+24-18

We add all the numbers together, and all the variables

16x+6

Back to the equation:

-(16x+6)



We get rid of parentheses

x-16x-6-9=0

We add all the numbers together, and all the variables

-15x-15=0

We move all terms containing x to the left, all other terms to the right

-15x=15

x=15/-15

x=-1

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