1x/7x+1x/6x=13

Solution for 1x/7x+1x/6x=13 equation:

1x/7x+1x/6x=13

We move all terms to the left:

1x/7x+1x/6x-(13)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R


We calculate fractions


6x^2/42x^2+7x^2/42x^2-13=0

We multiply all the terms by the denominator


6x^2+7x^2-13*42x^2=0

We add all the numbers together, and all the variables

13x^2-13*42x^2=0

Wy multiply elements

13x^2-546x^2=0

We add all the numbers together, and all the variables

-533x^2=0

a = -533; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-533)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-1066}=0$