1x2(x-12)=1+4x

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Solution for 1x2(x-12)=1+4x equation: 



1x^2(x-12)=1+4x

We move all terms to the left:

1x^2(x-12)-(1+4x)=0

We add all the numbers together, and all the variables

1x^2(x-12)-(4x+1)=0

We get rid of parentheses

1x^2(x-12)-4x-1=0

We move all terms containing x to the left, all other terms to the right

1x^2(x-12)-4x=1

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