If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1x^2+7x+12=0
We add all the numbers together, and all the variables
x^2+7x+12=0
a = 1; b = 7; c = +12;
Δ = b2-4ac
Δ = 72-4·1·12
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*1}=\frac{-8}{2} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*1}=\frac{-6}{2} =-3 $
| 1/x2+7/x+12=10 | | -4(2x-1)+5x=-12 | | 4x+2(x-1)=7x+2 | | 4x+2(x-3)=9x+1 | | 3(7-9x-5(5x+1)=-8(9x-4) | | 3+11x-1=9x+10-6x | | -26-(-10)=x/6 | | 3y+6=2y+6 | | -7-(-23)=x/4 | | x+(0.0875x)=108.75 | | 2(-3+3x=3-4(2x+1) | | 1/2m=12-m | | x=(12-9)5^2 | | 7w-(2+w)=6w-2 | | 3f/5+3=6 | | 8/x12=16 | | 2w-14w=72 | | 2w-14w=12 | | 3(t-3)+3=(2t-6) | | g+8=-7g | | h=-10-9h | | -6y+42=-4(y-9) | | -6(w-3)=-9w-3 | | -7u=3-6u | | -8w-40=-4(w+8) | | 5(w+3)+2w=29 | | 27=80n | | 28=4(v-2)+2v | | 7u+3(u+4)=-28 | | 3y-3+2y-4=y | | -7y+2(y-2)=16 | | 1.6-0.7x=0.5 |