1x2x+5+3x+4x-4=420

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Solution for 1x2x+5+3x+4x-4=420 equation: 



1x^2x+5+3x+4x-4=420

We move all terms to the left:

1x^2x+5+3x+4x-4-(420)=0

We add all the numbers together, and all the variables

1x^2x+7x-419=0

We move all terms containing x to the left, all other terms to the right

1x^2x+7x=419

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