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1x=3/4x
We move all terms to the left:
1x-(3/4x)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1x-(+3/4x)=0
We add all the numbers together, and all the variables
x-(+3/4x)=0
We get rid of parentheses
x-3/4x=0
We multiply all the terms by the denominator
x*4x-3=0
Wy multiply elements
4x^2-3=0
a = 4; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·4·(-3)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*4}=\frac{0-4\sqrt{3}}{8} =-\frac{4\sqrt{3}}{8} =-\frac{\sqrt{3}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*4}=\frac{0+4\sqrt{3}}{8} =\frac{4\sqrt{3}}{8} =\frac{\sqrt{3}}{2} $
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