1y+8(z-2)=7z+2

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Solution for 1y+8(z-2)=7z+2 equation:


Simplifying
1y + 8(z + -2) = 7z + 2

Reorder the terms:
1y + 8(-2 + z) = 7z + 2
1y + (-2 * 8 + z * 8) = 7z + 2
1y + (-16 + 8z) = 7z + 2

Reorder the terms:
-16 + 1y + 8z = 7z + 2

Reorder the terms:
-16 + 1y + 8z = 2 + 7z

Solving
-16 + 1y + 8z = 2 + 7z

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 1y + 16 + 8z = 2 + 16 + 7z

Reorder the terms:
-16 + 16 + 1y + 8z = 2 + 16 + 7z

Combine like terms: -16 + 16 = 0
0 + 1y + 8z = 2 + 16 + 7z
1y + 8z = 2 + 16 + 7z

Combine like terms: 2 + 16 = 18
1y + 8z = 18 + 7z

Add '-8z' to each side of the equation.
1y + 8z + -8z = 18 + 7z + -8z

Combine like terms: 8z + -8z = 0
1y + 0 = 18 + 7z + -8z
1y = 18 + 7z + -8z

Combine like terms: 7z + -8z = -1z
1y = 18 + -1z

Divide each side by '1'.
y = 18 + -1z

Simplifying
y = 18 + -1z

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