2((1-y)/3)+2y=1

Solution for 2((1-y)/3)+2y=1 equation:

2((1-y)/3)+2y=1

We move all terms to the left:

2((1-y)/3)+2y-(1)=0

We add all the numbers together, and all the variables

2((-1y+1)/3)+2y-1=0

We add all the numbers together, and all the variables

2y+2((-1y+1)/3)-1=0

We multiply all the terms by the denominator


2y*3)+2((-1y+1)-1*3)=0

We add all the numbers together, and all the variables

2y*3)+2((-1y+1)=0

Wy multiply elements

6y^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{12}=0$