2((3x-0.5)+(5x-2))=2(2x+3)+10x-5

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Solution for 2((3x-0.5)+(5x-2))=2(2x+3)+10x-5 equation: 



2((3x-0.5)+(5x-2))=2(2x+3)+10x-5

We move all terms to the left:

2((3x-0.5)+(5x-2))-(2(2x+3)+10x-5)=0



We calculate terms in parentheses: -(2(2x+3)+10x-5), so:

2(2x+3)+10x-5

We add all the numbers together, and all the variables

10x+2(2x+3)-5

We multiply parentheses

10x+4x+6-5

We add all the numbers together, and all the variables

14x+1

Back to the equation:

-(14x+1)



We get rid of parentheses

2((3x-0.5)+(5x-2))-14x-1=0

We add all the numbers together, and all the variables

-14x+2((3x-0.5)+(5x-2))-1=0

We move all terms containing x to the left, all other terms to the right

-14x+2((3x-0.5)+(5x-2))=1

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