2((y+2)(y+2))+4y+8=0

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Solution for 2((y+2)(y+2))+4y+8=0 equation:



2((y+2)(y+2))+4y+8=0
We add all the numbers together, and all the variables
4y+2((y+2)(y+2))+8=0
We multiply parentheses ..
2((+y^2+2y+2y+4))+4y+8=0
We move all terms containing y to the left, all other terms to the right
2((+y^2+2y+2y+4))+4y=-8

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