2(-0.5+5y)*(y)=10

Solution for 2(-0.5+5y)*(y)=10 equation:

2(-0.5+5y)(y)=10

We move all terms to the left:

2(-0.5+5y)(y)-(10)=0

We add all the numbers together, and all the variables

2(5y-0.5)y-10=0

We multiply parentheses

10y^2-1y-10=0

a = 10; b = -1; c = -10;
Δ = b2-4ac
Δ = -12-4·10·(-10)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{401}}{2*10}=\frac{1-\sqrt{401}}{20}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{401}}{2*10}=\frac{1+\sqrt{401}}{20}
$