2(-1-3b)+5b=0

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Solution for 2(-1-3b)+5b=0 equation: 



2(-1-3b)+5b=0

We add all the numbers together, and all the variables

2(-3b-1)+5b=0

We add all the numbers together, and all the variables

5b+2(-3b-1)=0

We multiply parentheses

5b-6b-2=0

We add all the numbers together, and all the variables

-1b-2=0

We move all terms containing b to the left, all other terms to the right

-b=2

b=2/-1

b=-2

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