2(-1/5+3z/2)=-37/5+z

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Solution for 2(-1/5+3z/2)=-37/5+z equation: 


z in (-oo:+oo)

2*((3*z)/2-1/5) = z-37/5 // - z-37/5

2*((3*z)/2-1/5)-z-(-37/5) = 0

2*((3*z)/2-1/5)-z+37/5 = 0

2*(3/2*z-1/5)-z+37/5 = 0

(2*5*(3/2*z-1/5))/5+(5*(-z))/5+37/5 = 0

2*5*(3/2*z-1/5)+5*(-z)+37 = 0

10*z-2+37 = 0

10*z+35 = 0

(10*z+35)/5 = 0

(10*z+35)/5 = 0 // * 5

10*z+35 = 0

10*z+35 = 0 // - 35

10*z = -35 // : 10

z = -35/10

z = -7/2

z = -7/2

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