2(-16c-7)-5c=4(c+17)

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Solution for 2(-16c-7)-5c=4(c+17) equation: 



2(-16c-7)-5c=4(c+17)

We move all terms to the left:

2(-16c-7)-5c-(4(c+17))=0

We add all the numbers together, and all the variables

-5c+2(-16c-7)-(4(c+17))=0

We multiply parentheses

-5c-32c-(4(c+17))-14=0



We calculate terms in parentheses: -(4(c+17)), so:

4(c+17)

We multiply parentheses

4c+68

Back to the equation:

-(4c+68)



We add all the numbers together, and all the variables

-37c-(4c+68)-14=0

We get rid of parentheses

-37c-4c-68-14=0

We add all the numbers together, and all the variables

-41c-82=0

We move all terms containing c to the left, all other terms to the right

-41c=82

c=82/-41

c=-2

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