2(-18+3x)-3x-19=10

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Solution for 2(-18+3x)-3x-19=10 equation: 



2(-18+3x)-3x-19=10

We move all terms to the left:

2(-18+3x)-3x-19-(10)=0

We add all the numbers together, and all the variables

2(3x-18)-3x-19-10=0

We add all the numbers together, and all the variables

-3x+2(3x-18)-29=0

We multiply parentheses

-3x+6x-36-29=0

We add all the numbers together, and all the variables

3x-65=0

We move all terms containing x to the left, all other terms to the right

3x=65

x=65/3

x=21+2/3

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