2(-2+-2b+4c)-b-c+4=0

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Solution for 2(-2+-2b+4c)-b-c+4=0 equation:


Simplifying
2(-2 + -2b + 4c) + -1b + -1c + 4 = 0
(-2 * 2 + -2b * 2 + 4c * 2) + -1b + -1c + 4 = 0
(-4 + -4b + 8c) + -1b + -1c + 4 = 0

Reorder the terms:
-4 + 4 + -4b + -1b + 8c + -1c = 0

Combine like terms: -4 + 4 = 0
0 + -4b + -1b + 8c + -1c = 0
-4b + -1b + 8c + -1c = 0

Combine like terms: -4b + -1b = -5b
-5b + 8c + -1c = 0

Combine like terms: 8c + -1c = 7c
-5b + 7c = 0

Solving
-5b + 7c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-7c' to each side of the equation.
-5b + 7c + -7c = 0 + -7c

Combine like terms: 7c + -7c = 0
-5b + 0 = 0 + -7c
-5b = 0 + -7c
Remove the zero:
-5b = -7c

Divide each side by '-5'.
b = 1.4c

Simplifying
b = 1.4c

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