2(-2+2)=3(-4+b)

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Solution for 2(-2+2)=3(-4+b) equation: 



2(-2+2)=3(-4+b)

We move all terms to the left:

2(-2+2)-(3(-4+b))=0

We add all the numbers together, and all the variables

-(3(b-4))+20=0



We calculate terms in parentheses: -(3(b-4)), so:

3(b-4)

We multiply parentheses

3b-12

Back to the equation:

-(3b-12)



We get rid of parentheses

-3b+12+20=0

We add all the numbers together, and all the variables

-3b+32=0

We move all terms containing b to the left, all other terms to the right

-3b=-32

b=-32/-3

b=10+2/3

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