2(-2r+7)=3(-2r-4)

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Solution for 2(-2r+7)=3(-2r-4) equation: 



2(-2r+7)=3(-2r-4)

We move all terms to the left:

2(-2r+7)-(3(-2r-4))=0

We multiply parentheses

-4r-(3(-2r-4))+14=0



We calculate terms in parentheses: -(3(-2r-4)), so:

3(-2r-4)

We multiply parentheses

-6r-12

Back to the equation:

-(-6r-12)



We get rid of parentheses

-4r+6r+12+14=0

We add all the numbers together, and all the variables

2r+26=0

We move all terms containing r to the left, all other terms to the right

2r=-26

r=-26/2

r=-13

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