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2(-2x+-4)+6=5+-3(x+1)
We move all terms to the left:
2(-2x+-4)+6-(5+-3(x+1))=0
We add all the numbers together, and all the variables
2(-2x-4)-(5+-3(x+1))+6=0
We use the square of the difference formula
2(-2x-4)-(5-3(x+1))+6=0
We multiply parentheses
-4x-(5-3(x+1))-8+6=0
We calculate terms in parentheses: -(5-3(x+1)), so:We add all the numbers together, and all the variables
5-3(x+1)
determiningTheFunctionDomain -3(x+1)+5
We multiply parentheses
-3x-3+5
We add all the numbers together, and all the variables
-3x+2
Back to the equation:
-(-3x+2)
-4x-(-3x+2)-2=0
We get rid of parentheses
-4x+3x-2-2=0
We add all the numbers together, and all the variables
-1x-4=0
We move all terms containing x to the left, all other terms to the right
-x=4
x=4/-1
x=-4
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